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Log(1i=(1�1i))=0logoddsof6dlog(2i=(1�2i))=1logoddsof6clog(3i=(1�3i))=2logoddsof6b Thethresholdprobabilitieskiaregivenbyantilogit(Kbecause1i62i63iitfollowsthat06162 Proportionalodds published presentations and documents on DocSlides.
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